“我们的研究显示,送礼者送出的礼物不令人满意,一个关键原因是送礼者急切地想看收礼者露出灿烂的笑容或发出开心的尖叫,但能引发这些反应的礼物往往不是那些被珍视的礼物。”

SAMPLE OUTPUT (file gift1.out)

dave 302
laura 66
owen -359
vick 141
amr -150

 

 

 

 

    简单水题,大意是有 NP
个朋友交换礼物(钱),输入第一行为 NP,接着 NP
行是朋友们的名字,再然后就是 NP
组数据,每组第一行是分发礼物的人的名字,第二行是他的初始资金和要分给 NG
个人,接着 NG 行是要分给的人名。

   
注意题目说了钱要分的平均(evenly)且不能有小数(no
fractional),因此我的做法是,在读入 NP 个名字时金钱初始化为 0,读入 NP
组数据时先减去他的初始金额,再加回(初始金额 %
NG),这样分给其他人的礼物金额就是(初始金额 / NG)。

    难点主要在于字符串的处理,我偷懒用了
map,为了效率 key 类型为 char* 而不是
string,这样就需要自己重载操作符。跟直接使用 struct
比较,也没什么优势,偷懒的代价。

 1 #include <iostream>
 2 #include <fstream>
 3 #include <cstring>
 4 #include <map>
 5 using namespace std;
 6 #define Native 0
 7 #if Native
 8     #define fin cin
 9     #define fout cout
10 #else
11     ifstream fin("gift1.in");
12     ofstream fout("gift1.out");
13 #endif
14 struct ptrCmp{
15     bool operator()(const char*s1,const char*s2)const{
16         return strcmp(s1,s2)<0;
17     }
18 };
19 map<char*,int,ptrCmp> mp;
20 map<char*,int,ptrCmp>::iterator it;
21 int main(){
22     int NP,NG,init,gift;
23     char tname[20],fri[10][20];
24 
25     fin>>NP;
26     for(int i=0;i<NP;i++){
27         fin>>fri[i];
28         mp[fri[i]]=0;
29     }
30     for(int i=0;i<NP;i++){
31         fin>>tname>>init>>NG;
32         mp[tname]-=init;
33         if(!NG) continue;
34         //题目数据良心,只有 0 0,如果出 500 0 之类的我这里就挂了
35         //上面两行代码应该交换下,这样应该就没问题了
36         mp[tname]+=init%NG;
37         gift=init/NG;
38         while(NG--){
39             fin>>tname;
40             mp[tname]+=gift;
41         }
42     }
43     for(int i=0;i<NP;i++)
44         fout<<fri[i]
45             <<' '
46             <<mp[fri[i]]
47             <<endl;
48     return 0;
49 }

    
好吧,官方代码再次把我吊打了,简明易懂很优美有木有!来欣赏下吧~

 1 #include <stdio.h>
 2 #include <string.h>
 3 #include <assert.h>
 4 
 5 #define MAXPEOPLE 10
 6 #define NAMELEN    32
 7 
 8 typedef struct Person Person;
 9 struct Person {
10     char name[NAMELEN];
11     int total;
12 };
13 
14 Person people[MAXPEOPLE];
15 int npeople;
16 
17 void
18 addperson(char *name)
19 {
20     assert(npeople < MAXPEOPLE);strcpy(people[npeople].name, name);
21     npeople++;
22 }
23 
24 Person*
25 lookup(char *name)
26 {
27     int i;
28 
29     /* look for name in people table */
30     for(i=0; i<npeople; i++)if(strcmp(name, people[i].name) == 0)return &people[i];
31 
32     assert(0);/* should have found name */
33 }
34 
35 int
36 main(void)
37 {
38     char name[NAMELEN];
39     FILE *fin, *fout;
40     int i, j, np, amt, ng;
41     Person *giver, *receiver;
42 
43     fin = fopen("gift1.in", "r");
44     fout = fopen("gift1.out", "w");
45 
46     fscanf(fin, "%d", &np);
47     assert(np <= MAXPEOPLE);
48 
49     for(i=0; i<np; i++) {fscanf(fin, "%s", name);addperson(name);
50     }
51 
52     /* process gift lines */
53     for(i=0; i<np; i++) {fscanf(fin, "%s %d %d", name, &amt, &ng);giver = lookup(name);for(j=0; j<ng; j++) {fscanf(fin, "%s", name);receiver = lookup(name);giver->total -= amt/ng;receiver->total += amt/ng;}
54     }
55 
56     /* print gift totals */
57     for(i=0; i<np; i++)fprintf(fout, "%s %d\n", people[i].name, people[i].total);
58     exit (0);
59 }

 

By Black Storm(使用为知笔记)

A study in September found that when 122 university students bought
iTune songs as a gift for friends, the recipient tended to like the gift
more if it reflected the buyer’s personal favourite music.

图片 1

PROGRAM NAME: gift1

图片 2

The study, published in the journal?Psychological Science, found
people are more likely to try to get a reaction from presents if they
are present to see them being opened.

Greedy Gift Givers

A group of NP (2 ≤ NP ≤ 10) uniquely named friends has decided to
exchange gifts of money. Each of these friends might or might not give
some money to any or all of the other friends. Likewise, each friend
might or might not receive money from any or all of the other friends.
Your goal in this problem is to deduce how much more money each person
gives than they receive.

The rules for gift-giving are potentially different than you might
expect. Each person sets aside a certain amount of money to give and
divides this money evenly among all those to whom he or she is giving a
gift. No fractional money is available, so dividing 3 among 2 friends
would be 1 each for the friends with 1 left over — that 1 left over
stays in the giver’s “account”.

In any group of friends, some people are more giving than others (or at
least may have more acquaintances) and some people have more money than
others.

Given a group of friends, no one of whom has a name longer than 14
characters, the money each person in the group spends on gifts, and a
(sub)list of friends to whom each person gives gifts, determine how much
more (or less) each person in the group gives than they receive.

‘Does anyone receive a present they actually want to keep?’ said
Professor Adrian Furnham, University College London psychologist.

Another experiment found gift-givers preferred personalized mugs but
people given them preferred less thoughtful ergonomic ones designed to
be easy to use.

SAMPLE INPUT (file gift1.in)

5
dave
laura
owen
vick
amr
dave
200 3
laura
owen
vick
owen
500 1
dave
amr
150 2
vick
owen
laura
0 2
amr
vick
vick
0 0

Researchers also gave some handy advice for couples, warning about the
dangers of giving presents of great cost too early in the relationship,
leading to over-hyped expectations.

A study has found gifts like books and money may not have the ‘wow’
factor but provide more satisfaction long-term.

INPUT FORMAT

Line 1: The single integer, NP
Lines 2..NP+1: Each line contains the name of a group member
Lines NP+2..end: NP groups of lines organized like this:

The first line in the group tells the person’s name who will be giving gifts.
The second line in the group contains two numbers: The initial amount of money (in the range 0..2000) to be divided up into gifts by the giver and then the number of people to whom the giver will give gifts, NGi (0 ≤ NGi ≤ NP-1).
If NGi is nonzero, each of the next NGi lines lists the the name of a recipient of a gift.

 

研究人员还发现,当人们收到比较贵重的礼物附带一些小的便宜的礼物时,通常会计算所有礼物的平均价值。

他们对198人以及600件圣诞礼物进一步分析后发现,像无线电钻这样的工具,往往在送礼时激起不了什么反应,但收礼者对此却有很高的满意度。而像纸杯蛋糕这样的花哨物品,虽然会激起不错的反应,比如让人一展笑颜,但带给收礼者的满意度却很低。

IMPORTANT NOTE

The grader machine is a Linux machine that uses standard Unix
conventions: end of line is a single character often known as ‘\n’.
This differs from Windows, which ends lines with two charcters, ‘\n’
and ‘\r’. Do not let your program get trapped by this!

SImilarly researcher found that people who receive a generous main
present as well as a smaller, cheaper gift, tend to work out the average
value of the set of gifts.

‘Our research suggests that a key reason that gift-givers give
unsatisfactory gifts is that they are keen to elicit bright smiles or
squeals of delight with their gifts and that such reactions are
frequently not paired with gifts that are deeply valued.’

OUTPUT FORMAT

The output is NP lines, each with the name of a person followed by a
single blank followed by the net gain or loss (final_money_value –
initial_money_value) for that person. The names should be printed in
the same order they appear on line 2 of the input.

All gifts are integers. Each person gives the same integer amount of
money to each friend to whom any money is given, and gives as much as
possible that meets this constraint. Any money not given is kept by the
giver.

买一份你认为某人会喜欢的礼物通常会让收礼物的人感到失望。

这项发表于《心理科学》期刊的研究还发现,如果人们会亲眼看到收礼的人打开礼物,他们会更倾向于通过礼物激起对方的反应。

The new advice may come as surprise for some long suffering shoppers
with the study, carried out by psychologists and other researchers,
suggesting you don’t need to overthink your presents.

在调查中,如果人们将亲眼看到收礼者打开礼物,近一半的送礼者会选择包装精美的礼物而不是选择更高级的礼物。如果是通过邮寄方式赠送礼物,选择精美包装的比例则降至不到28%。

(来源:沪江英语)

They are seen as boring and impersonal presents, given as the last
resort after running out of ideas. But putting a ten pound note in an
envelope or buying someone an interesting book is actually likely to
make them pretty happy.

Professor Furnham said that the ‘subtlety of the exchange’ can be most
easily seen when the choice of gift turns out to be completely wrong.

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